Evaluate f(5) for f(x) = |x - 3|.

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Multiple Choice

Evaluate f(5) for f(x) = |x - 3|.

Explanation:
Absolute value tells you how far a number is from zero, so |x − 3| is the distance from x to 3. Evaluate at x = 5: f(5) = |5 − 3| = |2| = 2. Since distance is nonnegative, the result is 2. This matches the idea that 5 is 2 units away from 3 on the number line.

Absolute value tells you how far a number is from zero, so |x − 3| is the distance from x to 3. Evaluate at x = 5: f(5) = |5 − 3| = |2| = 2. Since distance is nonnegative, the result is 2. This matches the idea that 5 is 2 units away from 3 on the number line.

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