If h(x) = x^3, what is h^{-1}(27)?

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Multiple Choice

If h(x) = x^3, what is h^{-1}(27)?

Explanation:
The inverse function undoes what the original function does. Since h(x) = x^3, you’re looking for the input x that cubed gives 27. So solve x^3 = 27. The cube root of 27 is 3, meaning h^{-1}(27) = 3. Only 3 produces 27 when cubed (since 9^3 = 729, (-3)^3 = -27, (1/3)^3 = 1/27).

The inverse function undoes what the original function does. Since h(x) = x^3, you’re looking for the input x that cubed gives 27. So solve x^3 = 27. The cube root of 27 is 3, meaning h^{-1}(27) = 3. Only 3 produces 27 when cubed (since 9^3 = 729, (-3)^3 = -27, (1/3)^3 = 1/27).

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