If P(A) = 0.25, P(B) = 0.4, and A and B are disjoint, P(A ∪ B) is?

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Multiple Choice

If P(A) = 0.25, P(B) = 0.4, and A and B are disjoint, P(A ∪ B) is?

Explanation:
When two events are disjoint, the probability that either one occurs is the sum of their individual probabilities. So P(A ∪ B) = P(A) + P(B) when A and B do not overlap. Here, that gives P(A ∪ B) = 0.25 + 0.40 = 0.65. This value is valid as a probability and reflects the chance that either A or B happens. The numbers 0.25 and 0.40 are each just the individual probabilities, and 0.15 would be the difference between them, not the probability of either event occurring.

When two events are disjoint, the probability that either one occurs is the sum of their individual probabilities. So P(A ∪ B) = P(A) + P(B) when A and B do not overlap. Here, that gives P(A ∪ B) = 0.25 + 0.40 = 0.65. This value is valid as a probability and reflects the chance that either A or B happens. The numbers 0.25 and 0.40 are each just the individual probabilities, and 0.15 would be the difference between them, not the probability of either event occurring.

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