Which value is in the domain of g(x) = sqrt(x - 2)?

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Multiple Choice

Which value is in the domain of g(x) = sqrt(x - 2)?

Explanation:
For the square root to be defined with real numbers, the radicand must be nonnegative. So for g(x) = sqrt(x - 2), we need x - 2 >= 0, which means x >= 2. Among the given values, only 2 satisfies this condition (since sqrt(0) = 0 is allowed). The others—1, 0, and -1—make x - 2 negative, which would not be a real value under the square root. Therefore, the value in the domain is 2.

For the square root to be defined with real numbers, the radicand must be nonnegative. So for g(x) = sqrt(x - 2), we need x - 2 >= 0, which means x >= 2. Among the given values, only 2 satisfies this condition (since sqrt(0) = 0 is allowed). The others—1, 0, and -1—make x - 2 negative, which would not be a real value under the square root. Therefore, the value in the domain is 2.

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